The source paper (Karlin–Klein–Oveis Gharan, arXiv:1908.00227, 2019) proved a randomized 1.49993-approximation for metric TSP instances whose subtour LP optimum is half-integral, with its integrality-gap consequence conditional on the Schalekamp–Williamson–van Zuylen (SWvZ) conjecture that the worst-case integrality gap of the subtour LP is attained on half-integral vertices. The source's subsidiary goals have since been met by other means: a randomized 3/2−ϵ3/2-\epsilon approximation for all metric instances (ϵ>10−36\epsilon>10^{-36}) has existed since 2020, the half-integral guarantee now stands at 1.49776, and the half-integral 2-edge-connected multisubgraph case admits a 4/34/3-approximation. The SWvZ conjecture itself remains open: the half-integral supremum lies in [4/3,1.49776][4/3,1.49776], the general gap in [4/3,3/2−ϵ][4/3,3/2-\epsilon], extreme-point enumeration up to n=15n=15 (17 for half-integral vertices) supports it, and no metric instance with integrality ratio above 4/34/3 — which any refutation would require — has ever been exhibited.

Background

The symmetric traveling salesperson problem (TSP) on a metric asks for a minimum-cost Hamiltonian cycle in a complete graph whose edge costs obey the triangle inequality. Its standard linear programming relaxation is the subtour LP (also called the subtour elimination LP or Held–Karp relaxation): minimize the cost of an edge vector xx subject to x(δ({v}))=2x(\delta(\{v\}))=2 for every vertex vv (each vertex has total incident value 2), x(δ(S))≥2x(\delta(S))\ge 2 for every vertex subset SS with 2≤∣S∣≤n−22\le |S|\le n-2 (no subtour may live inside a strict subset of the vertices), and xe≥0x_e\ge 0, where δ(S)\delta(S) denotes the set of edges with exactly one endpoint in SS. The integrality gap of this relaxation is the supremum, over all metric instances II, of OPT(I)/LP(I)\mathrm{OPT}(I)/\mathrm{LP}(I), the ratio of the optimal tour cost to the optimal LP value. The classical analysis of the Christofides–Serdyukov algorithm (take a minimum spanning tree and add a minimum-cost perfect matching on its odd-degree vertices) shows the gap is at most 3/23/2, while explicit constructions — the envelope-graph instances for graph metrics and the weighted kk-donut instances (two hand-built families of metric costs whose subtour LP optima are half-integral and whose optimal tours cost asymptotically 4/34/3 times the LP value) — show it is at least 4/34/3. Whether the gap is exactly 4/34/3 is the four-thirds conjecture, a long-standing open problem.

A feasible point of the subtour LP is half-integral if every coordinate lies in {0,1/2,1}\{0,1/2,1\}. Half-integral solutions are combinatorially rigid — their fractional (1/21/2-valued) edges form a structured union of cycles — and every known worst-case example for the subtour LP is half-integral. Schalekamp, Williamson and van Zuylen proved the Boyd–Carr conjecture that the worst-case ratio of an optimal 2-matching (an integral solution obeying only the degree constraints, i.e. a spanning collection of vertex-disjoint cycles) to the subtour LP is 10/910/9, and were led to conjecture that the integrality gap of the subtour LP is itself attained on half-integral vertices of the subtour polytope (the feasible region of the subtour LP).

The source paper proved the first better-than-3/23/2 guarantee on half-integral instances: given any half-integral solution xx of the subtour LP, sample a spanning tree from the maximum-entropy distribution over spanning trees whose marginal edge probabilities equal xx (the unique such distribution that is as uniform as possible), then correct parities by adding a minimum-cost perfect matching on the odd-degree vertices; the output tour has expected cost at most 1.49993 c(x)1.49993\,c(x), in randomized polynomial time. The analysis is a global amortized charging argument over the hierarchy of near-minimum cuts (cuts of LP value in [2,2+ϵ][2,2+\epsilon]), with a universal constant p≥1/27p\ge 1/27 and a per-edge expected gain p/240p/240; the authors identify the more complex structure of near-minimum cuts for non-half-integral solutions as the main barrier to extending the analysis. Consequently, if the Schalekamp–Williamson–van Zuylen conjecture holds, the integrality gap of the subtour LP is at most the best half-integral guarantee — 1.497761.49776 as of 2025. In the same line of work, the same authors later obtained a randomized 3/2−ϵ3/2-\epsilon approximation for all metric instances (ϵ>10−36\epsilon>10^{-36}), so the general integrality gap is also known to be below 3/23/2. The half-integral supremum is known to lie in [4/3,1.49776][4/3,1.49776] and the general gap in [4/3,3/2−ϵ][4/3,3/2-\epsilon].

Problem Statement

The problem is the Schalekamp–Williamson–van Zuylen half-integrality conjecture for the subtour LP, posed at the conclusion of their proof of the Boyd–Carr conjecture (in the original form: the worst-case integrality gap is achieved at costs for which an optimal solution of the subtour LP is also an optimal fractional 2-matching, i.e. instances for which adding the subtour-elimination constraints leaves the LP optimal value unchanged) and stated as Conjecture 1.1 of the source paper:

The integrality gap for the subtour LP is attained on half-integral vertices of the polytope.

Equivalently, in supremum form:

sup⁡I  OPT(I)LP(I)  =?  sup⁡IHI  OPT(IHI)LP(IHI)\sup_{I}\;\frac{\mathrm{OPT}(I)}{\mathrm{LP}(I)}\;\stackrel{?}{=}\;\sup_{I_{\mathrm{HI}}}\;\frac{\mathrm{OPT}(I_{\mathrm{HI}})}{\mathrm{LP}(I_{\mathrm{HI}})}

where II ranges over all finite symmetric metric TSP instances (arbitrarily many vertices), IHII_{\mathrm{HI}} over those whose subtour LP optimum is attained at a half-integral vertex, OPT\mathrm{OPT} denotes the optimal tour cost and LP\mathrm{LP} the optimal subtour LP value. The half-integral supremum is known to lie in [4/3,1.49776][4/3,1.49776] and the general gap in [4/3,3/2−ϵ][4/3,3/2-\epsilon] for some ϵ>10−36\epsilon>10^{-36}, so the two sides have not been separated. The conjecture is logically weaker than the four-thirds conjecture (a gap of exactly 4/34/3 would imply it, since half-integral envelope families already attain 4/34/3), and refuting it would mean exhibiting metric instances whose integrality ratio exceeds the half-integral supremum — necessarily exceeding 4/34/3, and hence simultaneously refuting the four-thirds conjecture.

References

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