Seymour's Second Neighborhood Conjecture (SNC) asserts that every oriented graph has a vertex whose second out-neighborhood is at least as large as its first out-neighborhood; it remains open in general. For an oriented graph DD, its missing graph GG is the graph formed by the pairs of vertices joined by no arc, and the dependency digraph ΔD\Delta_D has the missing edges of DD as vertices, with an arc from one missing edge to another when the first 'loses to' the second. Al-Mniny and Ghazal (Australas. J. Combin. 81 (2021), 58-88) introduced the class F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) of graphs GG such that ΔD\Delta_D is a vertex-disjoint union of directed paths for every oriented graph DD missing GG, proved SNC for oriented graphs missing any {C4,C‾4,S3,chair,chair‾}\{C_4,\overline{C}_4,S_3,\text{chair},\overline{\text{chair}}\}-free graph, and posed two open problems: (1) characterize F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) beyond the partial characterization they obtained, and (2) decide whether every oriented graph missing a graph in F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) — in the published formulation, in F(P⃗∪C⃗5)\mathcal{F}(\vec{\mathcal{P}}\cup\vec{\mathcal{C}}_5), which also permits one directed 5-cycle component in ΔD\Delta_D — satisfies the SNC. Both problems remain open.

Background

An oriented graph is a directed graph without loops and without digons, so each pair of distinct vertices is joined by at most one arc. For a vertex vv, the first out-neighborhood N+(v)N^+(v) is its set of out-neighbors, and the second out-neighborhood N++(v)N^{++}(v) is the set of vertices reachable from vv by a directed path of exactly two arcs but not lying in N+(v)N^+(v). Seymour's Second Neighborhood Conjecture (SNC), posed around 1990, asserts that every oriented graph has a vertex vv with ∣N+(v)∣≤∣N++(v)∣|N^+(v)|\le|N^{++}(v)|; such a vertex has the second neighborhood property (SNP). The conjecture is open in general. It was proved for tournaments (oriented complete graphs) by Fisher, following the tournament version conjectured by Dean and Latka, and Havet and Thomassé gave an influential shorter proof via median orders — a linear order of the vertices maximizing the number of forward arcs, whose last vertex (the feed vertex) has the SNP in tournaments. Kaneko and Locke verified the SNC for all oriented graphs of minimum out-degree at most 6.

A recurring route to dense, non-complete instances studies oriented graphs with few missing edges. A pair xyxy of vertices of an oriented graph DD is a missing edge if neither (x,y)(x,y) nor (y,x)(y,x) is an arc; vertices incident to no missing edge are whole, and the missing graph of DD is the graph GG whose vertex set is the non-whole vertices and whose edge set is the missing edges — one says DD is missing GG. Fidler and Yuster proved the SNC when the missing edges form a matching, a star, or a clique, introducing the dependency digraph: its vertices are the missing edges of DD, and there is an arc from the missing edge x1y1x_1y_1 to the missing edge x2y2x_2y_2 when x1→x2x_1\to x_2 with y2∉N+(x1)∪N++(x1)y_2\notin N^+(x_1)\cup N^{++}(x_1), and y1→y2y_1\to y_2 with x2∉N+(y1)∪N++(y1)x_2\notin N^+(y_1)\cup N^{++}(y_1) (one then says x1y1x_1y_1 loses to x2y2x_2y_2). A missing edge is good when one of its two orientations is 'convenient' in the sense that every vertex dominating one endpoint sees the other endpoint within directed distance two; Ghazal proved that a missing edge is good exactly when its in-degree in the dependency digraph is zero, and used this to prove the SNC for every oriented graph missing a threshold graph — a graph built by iteratively adding isolated or universal vertices, equivalently a {C4,C‾4,P4}\{C_4,\overline{C}_4,P_4\}-free graph, where CnC_n is the chordless nn-cycle, C‾4\overline{C}_4 its complement, and PnP_n the chordless nn-vertex path. For threshold graphs the dependency digraph is always empty.

Al-Mniny and Ghazal generalized this framework. For a family H\mathcal{H} of digraphs, a graph GG is H\mathcal{H}-forcing, written G∈F(H)G\in\mathcal{F}(\mathcal{H}), when for every oriented graph DD missing GG the dependency digraph ΔD\Delta_D belongs to H\mathcal{H}. They let P⃗\vec{\mathcal{P}} be the family of digraphs that are vertex-disjoint unions of directed paths. Using the structure theory of generalized combs — the graphs with no induced C4C_4, C‾4\overline{C}_4, C5C_5, S3S_3, chair, or co-chair, where the chair is the 5-vertex tree with edge set {xy,yz,zt,zv}\{xy,yz,zt,zv\}, the co-chair is its complement, and S3S_3 is a fixed 6-vertex graph defined by Ghazal — they proved: (i) among {C4,C5,S3}\{C_4,C_5,S_3\}-free graphs, the P⃗\vec{\mathcal{P}}-forcing graphs are exactly the generalized combs; (ii) F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) is closed under taking induced subgraphs; (iii) threshold graphs are P⃗\vec{\mathcal{P}}-forcing; and (iv) the 5-cycle C5C_5 and all {C4,C‾4,S3,chair,chair‾}\{C_4,\overline{C}_4,S_3,\text{chair},\overline{\text{chair}}\}-free graphs are P⃗∪C⃗5\vec{\mathcal{P}}\cup\vec{\mathcal{C}}_5-forcing, where P⃗∪C⃗5\vec{\mathcal{P}}\cup\vec{\mathcal{C}}_5 is the family of digraphs that are vertex-disjoint unions of directed paths together with at most one directed 5-cycle (the source's shorthand for this family is C⃗5={C⃗5}\vec{\mathcal{C}}_5=\{\vec{C}_5\} with C⃗5\vec{C}_5 the directed 5-cycle). Their main theorem proves the SNC for every oriented graph missing a {C4,C‾4,S3,chair,chair‾}\{C_4,\overline{C}_4,S_3,\text{chair},\overline{\text{chair}}\}-free graph, by the completion approach: orient the missing edges according to their behavior in the dependency digraph so as to obtain a tournament, take a median order, and show its feed vertex retains the SNP when the added arcs are removed — the long case analysis being driven exactly by ΔD\Delta_D being a disjoint union of directed paths plus possibly one directed 5-cycle. As corollaries, the SNC holds for oriented graphs missing a generalized comb, a comb, a threshold graph, or C5C_5.

The paper ends by posing the following two open problems: characterize F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) in full generality, and decide whether membership in the forcing class alone — without any additional forbidden-induced-subgraph hypothesis — already guarantees the SNC. The two halves are tightly linked: the first supplies the structural language in which the second, conjectural half is posed, and together they delineate the exact scope of the dependency-digraph/median-order method inside the broader missing-graph program for the SNC.

Problem Statement

Throughout, an oriented graph is a directed graph without loops and without digons, so each pair of distinct vertices is joined by at most one arc. For a vertex vv of an oriented graph, N+(v)N^+(v) denotes the set of out-neighbors of vv, and N++(v)N^{++}(v) denotes the set of vertices reachable from vv by a directed path of exactly two arcs and not belonging to N+(v)N^+(v). A pair of vertices of an oriented graph DD is a missing edge when neither of the two arcs between them is present; the missing graph of DD is the graph whose vertex set is the set of vertices of DD incident with at least one missing edge and whose edge set is the set of missing edges, and one says that DD is missing GG when GG is the missing graph of DD. Write CnC_n for the chordless cycle on nn vertices and C‾4\overline{C}_4 for the complement of C4C_4.

Let P⃗\vec{\mathcal{P}} be the family of digraphs each of which is a vertex-disjoint union of directed paths, and let P⃗∪C⃗5\vec{\mathcal{P}}\cup\vec{\mathcal{C}}_5 be the family of digraphs that are vertex-disjoint unions of directed paths together with at most one directed cycle of length 5 (the source's shorthand is C⃗5={C⃗5}\vec{\mathcal{C}}_5=\{\vec{C}_5\} with C⃗5\vec{C}_5 the directed 5-cycle). For a family H\mathcal{H} of digraphs, let F(H)\mathcal{F}(\mathcal{H}) denote the class of graphs GG such that for every oriented graph DD missing GG, the dependency digraph ΔD\Delta_D belongs to H\mathcal{H}; the vertices of ΔD\Delta_D are the missing edges of DD, and there is an arc from the missing edge x1y1x_1y_1 to the missing edge x2y2x_2y_2 when x1→x2x_1\to x_2 with y2∉N+(x1)∪N++(x1)y_2\notin N^+(x_1)\cup N^{++}(x_1), and y1→y2y_1\to y_2 with x2∉N+(y1)∪N++(y1)x_2\notin N^+(y_1)\cup N^{++}(y_1) (one then says that x1y1x_1y_1 loses to x2y2x_2y_2). The source paper poses two linked problems:

(Problem A, their Problem 1). Characterize F(P⃗)\mathcal{F}(\vec{\mathcal{P}}): give a structural description of all graphs GG such that the dependency digraph of every oriented graph missing GG is a disjoint union of directed paths. The known partial answer is that, restricted to {C4,C5,S3}\{C_4,C_5,S_3\}-free graphs (where S3S_3 is the specific 6-vertex graph defined by Ghazal, 2018), F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) consists exactly of the generalized combs, that is, the graphs with no induced C4C_4, C‾4\overline{C}_4, C5C_5, S3S_3, chair, or co-chair, where the chair is the 5-vertex tree with edge set {xy,yz,zt,zv}\{xy,yz,zt,zv\} and the co-chair is its complement; the characterization is required without this restriction.

(Problem B, their Problem 2). Does every oriented graph missing a graph G∈F(P⃗∪C⃗5)G\in\mathcal{F}(\vec{\mathcal{P}}\cup\vec{\mathcal{C}}_5) satisfy Seymour's Second Neighborhood Conjecture, i.e., contain a vertex vv with ∣N+(v)∣≤∣N++(v)∣|N^+(v)|\le|N^{++}(v)|? It is known that the answer is yes when GG is additionally {C4,C‾4,S3,chair,chair‾}\{C_4,\overline{C}_4,S_3,\text{chair},\overline{\text{chair}}\}-free (this is the main theorem of the source); the question is whether the forcing condition alone suffices.

The two deliverables share one scientific objective — determining the exact scope of the dependency-digraph/median-order method in the missing-graph program for the SNC — with Problem A supplying the structural description of the forcing class and Problem B deciding whether that structural condition already guarantees the conjecture. The two problems are logically independent: a characterization of F(P⃗)\mathcal{F}(\vec{\mathcal{P}}) does not by itself decide the SNC question, and a resolution of Problem B does not by itself characterize F(P⃗)\mathcal{F}(\vec{\mathcal{P}}), so neither answer substitutes for the other and each requires its own resolution.

References

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