Müyesser and Pokrovskiy proved that for all sufficiently large nn, a subsquare A×BA\times B of the multiplication table of a finite group GG, with ∣A∣=∣B∣=n|A|=|B|=n, contains a transversal unless either AA and BB are cosets of a subgroup violating the Hall–Paige condition, or A×BA\times B is obtained from the table of an elementary abelian 2-group by deleting two rows and two columns whose elements sum to zero. Their probabilistic absorption methods are intrinsically asymptotic, and they conjecture the classification holds for every finite order. This problem asks for a proof or disproof of that all-nn conjecture; its cyclic even-order specialization is the second case of Snevily's 1999 conjecture, open ever since it was posed.

Background

A complete mapping of a finite group GG is a bijection ϕ:G→G\phi:G\to G such that x↦xϕ(x)x\mapsto x\phi(x) is also a bijection; equivalently, it is a transversal of the multiplication table M(G)M(G), the Latin square whose rows and columns are indexed by the elements of GG and whose entry in row gg and column hh is ghgh. Here a Latin square is an n×nn\times n array filled with nn symbols so that each symbol appears exactly once in each row and each column, and a transversal is a selection of nn cells no two of which share a row, a column, or a symbol. Complete mappings were introduced by Hall and Paige (1955), who showed that a necessary condition for their existence is the Hall–Paige condition: the product of all elements of GG must be trivial in the abelianization Gab=G/G′G^{\mathrm{ab}}=G/G' (where G′G' is the commutator subgroup), which is equivalent to every Sylow 2-subgroup of GG (a subgroup whose order is the largest power of 2 dividing ∣G∣|G|) being trivial or non-cyclic. They conjectured sufficiency, confirmed in 2009 by Wilcox, Evans, and Bray using the classification of finite simple groups; Eberhard, Manners, and Mrazović (2022) later gave an analytic proof for large groups together with a precise asymptotic count of complete mappings.

A natural refinement, due to Snevily (1999), concerns subsquares: deleting rows and columns from M(G)M(G) should only make transversals easier to find, so which subsquares fail to have one? Formally, for A,B⊆GA,B\subseteq G with ∣A∣=∣B∣=n|A|=|B|=n, the subsquare A×BA\times B is the n×nn\times n array with rows indexed by AA, columns by BB, and entry abab in row aa and column bb. Snevily conjectured that for abelian GG of odd order every subsquare has a transversal, and that for cyclic GG of even order the only obstructions are subsquares that are cosets of the multiplication table of an even-order cyclic subgroup. The odd-order claim was proved for prime-order cyclic groups by Alon (2000) via the Combinatorial Nullstellensatz (a polynomial-method tool for forcing solutions of systems over fields), extended to all odd-order cyclic groups by Dasgupta, Károlyi, Serra, and Szegedy (2001), and settled for all abelian groups of odd order by Arsovski (2011) using character theory. The even-order cyclic case remains open. In even order a second genuine obstruction exists: in an elementary abelian 2-group (Z2)k(\mathbb{Z}_2)^k, deleting two rows and two columns whose labelling elements sum to zero produces a subsquare with no transversal.

Müyesser and Pokrovskiy (preprint 2022, Inventiones mathematicae 2025) proved a far-reaching common generalization for large groups. Their main theorem, proved with probabilistic absorption techniques (a method that pre-allocates a flexible reservoir of cells and then completes an almost-solution to an exact one), shows that for random-like equal-sized subsets A,B,CA,B,C of a sufficiently large group GG satisfying the natural sum condition ∑A+∑B=∑C\sum A+\sum B=\sum C in GabG^{\mathrm{ab}}, there is a bijection ϕ:A→B\phi:A\to B with x↦xϕ(x)x\mapsto x\phi(x) a bijection from AA onto CC. Among its consequences is the following classification, valid for all nn beyond some absolute constant n0n_0: the subsquare A×BA\times B has a transversal unless either (i) AA and BB are a left and a right coset of a subgroup HH failing the Hall–Paige condition (so A×BA\times B is a translate of M(H)M(H), which has no transversal), or (ii) A×BA\times B arises from the multiplication table of some (Z2)k(\mathbb{Z}_2)^k by deleting two rows and two columns whose entries sum to zero. (This is an informal description; the precise formalization of the two exceptional families, in which the deleted-index sets may be arbitrary left translates by elements g1,g2∈Gg_1,g_2\in G, is given in the Problem Statement below.) This confirms both cases of Snevily's conjecture for sufficiently large subsquares, and as further consequences the paper characterises, for sufficiently large orders, the sequenceable groups (those whose elements admit an ordering with all partial products distinct), the RR-sequenceable groups (the variant in which all partial products except the total are distinct and the total is the identity), and the harmonious groups (those whose elements admit an ordering in which the products of consecutive pairs are all distinct).

The proof is intrinsically asymptotic — the absorption and nibble arguments (the latter a randomized greedy process that covers almost all of a structure, leaving a small remainder for the absorber) need nn tending to infinity — and the authors state that it seems hopeless to push their methods down to small nn. Nevertheless they conjecture that the classification itself is true for every nn, and this is the problem audited here.

Problem Statement

Prove, or disprove, Conjecture 7.1 of Müyesser and Pokrovskiy: the following holds for every nn (with no lower bound on nn). Let GG be a finite group and let A,B⊆GA,B\subseteq G with ∣A∣=∣B∣=n|A|=|B|=n. Then the subsquare A×BA\times B (rows indexed by AA, columns by BB, entry abab in row aa and column bb) contains a transversal — nn cells with no two sharing a row, a column, or a symbol — unless there exist an integer k≥1k\ge 1, elements g1,g2∈Gg_1,g_2\in G, and a subgroup H⊆GH\subseteq G such that one of the following holds:

  1. HH fails the Hall–Paige condition (equivalently, its Sylow 2-subgroups are nontrivial and cyclic), and A=g1HA=g_1H and B=Hg2B=Hg_2; or
  2. H≅(Z2)kH\cong(\mathbb{Z}_2)^k and g1A=H∖{a1,a2}g_1A=H\setminus\{a_1,a_2\}, g2B=H∖{b1,b2}g_2B=H\setminus\{b_1,b_2\} for distinct a1,a2∈Ha_1,a_2\in H and distinct b1,b2∈Hb_1,b_2\in H with a1+a2+b1+b2=0a_1+a_2+b_1+b_2=0 (the sum computed in the abelian group HH, written additively).

The quantitative strengthenings of the underlying matching theorem (the source paper's Conjecture 7.2 and Problems 7.3–7.4 on optimal error bounds), and the enumerative, strong-complete-mapping, and Kézdy–Snevily directions from the same concluding section, are neighboring open questions and are not part of the completion boundary of this problem.

References

  1. Alp Müyesser and Alexey Pokrovskiy, A random Hall–Paige conjecture, Inventiones mathematicae 240:779–867 (2025), DOI 10.1007/s00222-025-01328-x; preprint arXiv:2204.09666, https://arxiv.org/abs/2204.09666
  2. Marshall Hall and L. J. Paige, Complete mappings of finite groups, Pacific Journal of Mathematics 5:541–549 (1955), DOI 10.2140/pjm.1955.5.541, https://doi.org/10.2140/pjm.1955.5.541
  3. H. S. Snevily, The Cayley addition table of Z_n, The American Mathematical Monthly 106(6):584–585 (1999), DOI 10.1080/00029890.1999.12005088, https://doi.org/10.1080/00029890.1999.12005088
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  12. Yutong Zhang and Yaoran Yang, The least non-partitionable zero-sum subset for zero-sum triples in finite abelian groups, preprint arXiv:2606.13764 (2026), https://arxiv.org/abs/2606.13764